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Define simple harmonic motion. Show that the motion of projection of particle performing uniform circular motion, on any diameter is simple harmonic. |
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Answer» Solution :Simple harmonic motion: A body is said to be inS.H.M, If acceleration is directly proportional to its displacement. Acts opposite in direction towards a fixed point. Relation between uniform circular motion and S.H.M.:Let a particle 'P' is rotating in a circular path of radius 'r' with a uniform angular velocity `'omega'`. After time 't' it goes to a new position 'P'. Draw normals form 'P' on to the X-axis and on the Y-axis. Let ON and OM are the PROJECTIONS on X and Y axis respectively. As the paritcle is in motion it will subtend an angle `theta=omegat` at the centre. From triangle OPN ON=OP `costheta` But `OP = r and theta=omegat` `therefore` Displacement of particle. P on X-axis at any time t is `X=rcosomegat"".............(1)` From triangle OPM `OM=Y-OPsintheta` But `OP=r and theta=omegat` `therefore` Displacement of particle P on Y-axis is `Y=rsin omegat""..............(2)` As the particle rotate in a circular path the FOOT of the perpendicular OM and ON will oscillatiate with in the limits `X to X^(1) and Y to Y^(1)`. At any point the displacement of particle P is given by `OP^(2)=OM^(2)+ON^(2)` SINCE `OM=X=rcosomegat and ON=Y=r sinomegat.` So a uniform circular motion can be treated as a combination of two mutually perpendicular simple harmonic motions. |
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