Derive an expression for magnitude of magnetic dipole momentof a revol

1.	Derive an expression for magnitude of magnetic dipole momentof a revolving electron.A circular coil of 300 turns and diameter 14 cm carries a currentof 15A. Calculate the magnitude of the magnetic dipole momentassociated with the coil.
Answer» The magnitude(M) of the magnetic DIPOLE moment = 69.27 Am^2 Explanation: Assuming the angular velocity with which the electron rotates about an AXIS be w, so, Angular velocity = w rod/s w = 2πf f = (w/2π)Hz As we know, Rotating charge follows generated current, Equivalent current = qf = wq/2π The GIVEN case can be considered as a case of a current-bearing loop. Assuming the RADIUS be R, so vector r = πr^2n n cap - direction is ⊥ to the rotation, Magnetic moment = IA *= wq/2π πr^2 = wqr^2/2 In favor of an electron, q = e = 1.6×10^-19 C ∴ Magnetic moment = wer^2/2 Given, N = 300, D = 14cm r = 14/2 = 7 × 10^-2m (current) i = 15 A Magnetic dipole moment associated with the coil, M = NI(πr^2) ⇒ M = 300 * 15 * 22/7 * (7 × 10^-2)^2 ∵ M = 69.27 Am^2 Learn more:** Magnitude brainly.in/question/8036385

Derive an expression for magnitude of magnetic dipole momentof a revolving electron.A circular coil of 300 turns and diameter 14 cm carries a currentof 15A. Calculate the magnitude of the magnetic dipole momentassociated with the coil.

Answer»

Explanation:

Assuming the angular velocity with which the electron rotates about an AXIS be w,

so,

Angular velocity = w rod/s

w = 2πf

f = (w/2π)Hz

As we know,

Rotating charge follows generated current,

Equivalent current = qf

= wq/2π

The GIVEN case can be considered as a case of a current-bearing loop.

Assuming the RADIUS be R, so

vector r = πr^2n

n cap - direction is ⊥ to the rotation,

Magnetic moment = IA

= wq/2π * πr^2

= wqr^2/2

In favor of an electron,

q = e = 1.6×10^-19 C

∴ Magnetic moment = wer^2/2

Given,

N = 300,

D = 14cm

r = 14/2 = 7 × 10^-2m

(current) i = 15 A

Magnetic dipole moment associated with the coil,

M = NI(πr^2)

⇒ M = 300 * 15 * 22/7 * (7 × 10^-2)^2

∵ M = 69.27 Am^2

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