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Derive for parallel connection equivalent resistance(r) = \frac{R1*R2}{R1+R2} |
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Answer» SEE let there be n resistors of resistance r1,r2,r3 ...... rn so in parallel connection the potential difference remains same but the current spreads in different resisters in i1,i2,i3 ...... in so let the total potential difference be V current be I and equivalent resistance be R so using junction rule I = i1 + i2 + i3 + . . . + in so we KNOW I = so cancelling V from both sides we GET PROVED |
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