1.

"Derive R"=(rhol)/(A).

Answer»

Solution :1. Resistance of a conductor `(R)` is directly proportional to its LENGTH (l) for a constant potential difference.
`Ralphal""-(1)`
2. Resistance of a conductor is inversely proportional to its cross section area.
`Ralpha(1)/(A)""-(1)`
3. From (1) and (2), we get `Ralpha(1)/(A)` (at constant temperature)
`rArrR=(rho1)/(A)`
Where, `RHO` is a proportionalty constant and it is CALLED specific resitance or RESISTIVITY.
4. The S.I. unit of resistivity is `Omega-m.`


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