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"Derive R"=(rhol)/(A). |
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Answer» Solution :1. Resistance of a conductor `(R)` is directly proportional to its LENGTH (l) for a constant potential difference. `Ralphal""-(1)` 2. Resistance of a conductor is inversely proportional to its cross section area. `Ralpha(1)/(A)""-(1)` 3. From (1) and (2), we get `Ralpha(1)/(A)` (at constant temperature) `rArrR=(rho1)/(A)` Where, `RHO` is a proportionalty constant and it is CALLED specific resitance or RESISTIVITY. 4. The S.I. unit of resistivity is `Omega-m.` |
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