Derive the expression for oscillation due to gravity

1.	Derive the expression for oscillation due to gravity
Answer» Explanation: TIME PERIOD T= time required to complete one oscillation. At equilibrium T 0 =mg. For small displacement θ Restoring force =−mgsinθ for small θ sinθ≈θ ⇒fe=−mgθ=−mg( l x ) ACCELERATION a= m fe = l −g .x We know for SHM, a=−W 2 x ⇒ On comparing we get w= l g ∴ Time period of oscillation T= w 2Π =2Π g l .

Answer»

Explanation:

TIME PERIOD T= time required to complete one oscillation.

At equilibrium T

=mg.

For small displacement θ

Restoring force =−mgsinθ

for small θ sinθ≈θ

⇒fe=−mgθ=−mg(

)

ACCELERATION a=

−g

We know for SHM, a=−W

⇒ On comparing we get w=

∴ Time period of oscillation T=

2Π

=2Π

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Derive the expression for oscillation due to gravity​

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Derive the expression for oscillation due to gravity