Derive the following equation of motion by the graphical method . V 2=

1.	Derive the following equation of motion by the graphical method . V 2=U 2+2as Where their symbols have their usual meaning .
Answer» Answer: Consider the velocity-time graph of a body as shown below: The initial velocity is u at the POINT A which changes from A to B at uniform RATE in time t. Let v be the final velocity which is equal to BC in the graph. OC represents the time t. A perpendicular is DRAWN CB from point C and AD is drawn parallel to OC. BE is the perpendicular from point B to OE. The area under OABC is the distance travelled s. Distance travelled, s = area of TRAPEZIUM OABC OA + CB = u + v OC = t Therefore, v2 = u2 + 2as

Derive the following equation of motion by the graphical method . V 2=U 2+2as Where their symbols have their usual meaning .

Answer»

Answer:

Consider the velocity-time graph of a body as shown below:

The initial velocity is u at the POINT A which changes from A to B at uniform RATE in time t. Let v be the final velocity which is equal to BC in the graph. OC represents the time t. A perpendicular is DRAWN CB from point C and AD is drawn parallel to OC. BE is the perpendicular from point B to OE. The area under OABC is the distance travelled s.

Distance travelled, s = area of TRAPEZIUM OABC

OA + CB = u + v

OC = t

Therefore, v2 = u2 + 2as

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