1.

Derive the relation R=R_1+R_2+R_3. When resistors are joined in series.

Answer»

Solution :In series combination, the same current FLOWS in all the resistances but the potential difference across each of the resistance is DIFFERENT.
According to Ohm law , we have
`V_1=IR_1,V_2=IR_2,V_3=IR_3`
IF the total potential difference between A and B is V, then
`V=V_1+V_2+V_3`
`=IR_1+IR_2+IR_3=I(R_1+R_2+R_3)`
LET the equivalent resistance be R, then
V=IR
and hence `IR=I(R_1+R_2+R_3)`
`implies R=R_1+R_2+R_3`


Discussion

No Comment Found

Related InterviewSolutions