InterviewSolution
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InterviewSolution
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Determine `Delta U^(@) ` at 300K for the following reaction using the listed enthalpies of reaction : `4CO(g)+8H_(2)(g)to3CH_(4)(g)+CO_(2)(g)+2H_(2)O(l)` `C("graphite")+(1)/(2)O_(2)(g)to CO(g), DeltaH_(1)^(@)=-110.5KJ`` CO(g)(1)/(2)O_(2)(g)toCO_(2)(g), DeltaH_(2)^(@)=-282.9KJ` `H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l), DeltaH_(3)^(@)=-285.8KJ` `C("graphite")+2H_(2)(g)to CH_(4)(g), DeltaH_(4)^(@)=-74.8KJ`A. `-653.5 KJ`B. `-686.2 KJ`C. `-747.4 KJ`D. None of these |
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Answer» Correct Answer - D `DeltaH^(@) =- 3DeltaH_(1)^(@)DeltaH_(2)^(@) + 2DeltaH_(3)^(@) + 3DeltaH_(4)^(@)` `=-747.4` KJ `DeltaH^(@) =DeltaU^(@) + Deltan_(g) RT , "where" Deltan_(g) =- 8` `747.4 = DeltaU^(@) - (8xx8.314 xx300)/(1000)` `DeltaU^(@)=-747.44` KJ. |
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