InterviewSolution
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InterviewSolution
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Determine `Delta U^(@) ` at 300K for the following reaction using the listed enthalpies of reaction : `4CO(g)+8H_(2)(g)to3CH_(4)(g)+CO_(2)(g)+2H_(2)O(l)` `C("graphite")+(1)/(2)O_(2)(g)to CO(g), DeltaH_(1)^(@)=-110.5KJ`` CO(g)(1)/(2)O_(2)(g)toCO_(2)(g), DeltaH_(2)^(@)=-282.9KJ` `H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l), DeltaH_(3)^(@)=-285.8KJ` `C("graphite")+2H_(2)(g)to CH_(4)(g), DeltaH_(4)^(@)=-74.8KJ`A. `-653.5` kJB. `-686.2` kKJC. `-747.4` kJD. None of these |
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Answer» Correct Answer - D `DeltaH^(@)=-3DeltaH_(1)^(@)+DeltaH_(2)^(@)+2DeltaH_(3)^(@)+3DeltaH_(4)^(@)` `=-747.4kJ` `DeltaH^(@)=DeltaU^(@)+Deltan_(g)RT," where " Deltan_(g)=-8` `-747.4=DeltaU^(@)=(8xx8.314xx300)/(1000)` `DeltaU^(@)=-727.44kJ` |
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