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Determine enthalpy of formation for `H_(2)O_(2)(l)`, using the listed enthalpies of reaction : `N_(2)H_(4)(l)+2H_(2)O_(2)(l)toN_(2)(g)+4H_(2)O(l)`, `" "Delta_(r)H_(1)^(@)=-818kJ//mol` `N_(2)H_(4)(l)+O_(2)(g)toN_(2)(g)+2H_(2)O(l)` `" "Delta_(r)H_(2)^(@)=-622kJ//mol` `H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l)" "Delta_(r)H_(3)^(@)=-285kJ//mol`A. `-383` kJ/molB. `-187` kJ/molC. `-498` kJ/molD. None of these |
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Answer» Correct Answer - B For `H_(2)(g)+O_(2)(g)rarrH_(2)O_(2)(l)` `Delta_(f)H^(@)(H_(2)O_(2),l)=Delta_(r )H_(3)^(@)+(Delta_(r )H_(2)^(@))/(2)-(Delta_(r )H_(1)^(@))/(2)` |
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