Determine k, so that `K^(2)+4k+8, 2k^(2)+3k+6` and `3k^(2)+4k+4` are t – InterviewSolution

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1.	Determine k, so that `K^(2)+4k+8, 2k^(2)+3k+6` and `3k^(2)+4k+4` are three consecutive terms of an AP.
Answer» Since, `k^(2)+4k+8, 2k^(2)+3k+6` and `3k^(2) +4k+4` are consecutive terms of an AP. ` :. 2k^(2)+3k+6-(k^(2)+4k+8)=3k^(2)+4k+4-(2k^(2)+3k+6)=` Common difference `implies 2k^(2)+3k+6-k^(2)-4k-8=3k^(2)+4k+4-2k^(2)-3k-6` ` implies " " k^(2)-k-2=k^(2)+k-2` `implies " " -k=kimplies2k=0impliesk=0`

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