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The third term and nineth terms of an A.P. are 4 and -8 respectively. Find which term of A.P is equal to 0. |
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Answer» Let `a` is the first term of `A.P.` and `d` is the common difference of the `A.P.` Then, `a+2d = 4->(1)` `a+8d = -8->(2)` Subtracting (2)-(1), `a+8d-a-2d = -8-4` `d = -2` Therefore, `a+2(-2) = 4 => a = 8` Let `n` th term of this `A.P.` is `0`. `:. 8+(n-1)(-2) = 0` `=> 8-2n+2 = 0` `=>2n = 10` `=> n = 5` `:.5^(th)` term of the `A.P.` will be `0`. |
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