1.

Determine the AP whose 3rd term is 5 and the 7th term is 9.

Answer»

We have

a3 = a + (3 – 1) d = a + 2d = 5  .....(1)

and a7 = a + (7 – 1) d = a + 6d = 9  ......(2)

Solving the pair of linear equations (1) and (2), we get

a = 3, d = 1

Hence, the required AP is 3, 4, 5, 6, 7, . . .



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