1.

Determine the AP whose fifth term is 19 and the difference of the eighth term from the thirteenth term is 20.

Answer»

We know that,

The first term of an AP = a

And, the common difference = d.

According to the question,

5th term, a5 = 19

Using the nth term formula,

an = a + (n – 1)d

We get,

a + 4d = 19

a = 19 – 4d …(1)

Also,

20th term – 8th term = 20

a + 19d – (a + 7d) = 20

12d = 20

d = 4/3

Substituting d = 4/3 in equation 1,

We get,

a = 19 – 4(4/3)

a = 41/3

Then, the AP becomes,

41/3, 41/3 + 4/3 , 41/3 + 2(4/3)

41/3, 15, 49/3



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