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Determine the enthalpy of formation of `B_(2)H_(6)`(g) in kJ/mol of the following reaction : `B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(3)(s)+3H_(2)O(g)`, Given : `Delta_(r )H^(@)=-1941 " kJ"//"mol", " "DeltaH_(f)^(@)(B_(2)O_(3),s)=-1273" kJ"//"mol,"` `DeltaH_(f)^(@)(H_(2)O,g)=-241.8 " kJ"//"mol"`A. `-75.6`B. `+75.6`C. `-57.4`D. `-28.4` |
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Answer» Correct Answer - C `-1941 =-1273 + 3 (-241.8)-(Delta_(f)H)B_(2)H_(6)` `(Delta_(f)H)_(B_(2)H_(6))=-1273-725.4 + 1941 =-57.4` |
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