1.

Determine the flow rate of water, if the catchment area of hydroelectric power is 2500 km^2, with an average rainfall of 160cm. the percolation and evaporation losses account for 19%?(a) 9639.8 M^3/s(b) 42.8 M^3/s(c) 859.63 M^3/s(d) 2342 M^3/sThis question was posed to me in an interview for job.I need to ask this question from Hydrographs topic in chapter Hydro Electric Power Plant of Energy Engineering

Answer»

Correct choice is (a) 9639.8 M^3/s

Explanation: Amount of water available for power GENERATION,

QA = A X H X (1-y)

= 2500 X 10^6 X 160/100 (1-0.19)

= 3.04 X 10^11m^3

Flow rate of water,

Q = Qa/(365 X 24 X 60 X 60)

= (3.04 X 10^-6)/(365 X 24 X 60 X 60)= 9639.8 M^3/s.


Discussion

No Comment Found

Related InterviewSolutions