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Detrmine the maximum acceleration of the train in which a box lying on the floor will remain stationary given that the coefficient of static friction between the box and the train s floor is 0.15 given `g = 10 m//s^(2)` . |
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Answer» As acceleration (a) of box is due to static friction , therefore, `ma = f le mu_(s) R le mu_(s) mg` `a le mu_(s) g ` or ` a_(max) = mu_(s) g = 0. 15 xx 10 = 1.5 m// s^(2)` . |
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