Diagonals AC and BD of `square ABCD` intersect each other at point P. – InterviewSolution

InterviewSolution

1.	Diagonals AC and BD of `square ABCD` intersect each other at point P. Show that `ar(triangle APB)xxar(triangle CPD)=ar(triangle APD)xxar(triangle BPC)`
Answer» `AM _\|_ BD & CN _\|_ BD ` `L.H.S.= area(/_APB)xxarea(/_CPD)` `=1/2xx(BPxxAM)xx1/2(PDxxCN)` `=1/2(BPxxCN)xx1/2(PDxxAM)` `=area(/_BPC)xxarea(/_APD)` `L.H.S=R.H.S`

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