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Diazonium salt decomposes as `C_(6)H_(5)N_(2)^(o+)Cl^(ɵ) rarrC_(6)H_(5)Cl+N_(2)` at `10^(@)C`, the evolution of `N_(2)` becomes two first faster when the initial concentration of the salt is doubled. Thus, it isA. A first order reactionB. A second order reactionC. Independent of the initial concentration of reactantD. A zero order reaction. |
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Answer» Correct Answer - A `r_(1) = k["salt"]^(n)` `r_(2) = 2r_(1) = k[2 "salt"]^(n)`. `(2r_(1))/(r_(1)) = (2)^(n)` `(2)^(1) = (2)^(n)` `n = 1` Correct Answer - A `r_(1) = k["salt"]^(n)` `r_(2) = 2r_(1) = k[2 "salt"]^(n)`. `(2r_(1))/(r_(1)) = (2)^(n)` `(2)^(1) = (2)^(n)` `n = 1` |
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