1.

Differentiate ` Sin^2 (theta^2 +1)` w.r.t. `theta^2`

Answer» `y=sin^2(theta^2+1)`
`v=theta^2`
`dy/dv=((dy)/(d theta))/((dv)/(d theta))`
`dy/(dtheta)=sin^2(V+1)=2sin(V+1)*cos(V+1)(dv)/(d theta)`
`=2sin(theta^2+1)cos(theta^2+1)`
`=sin2(theta^2+1)`.


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