

InterviewSolution
Saved Bookmarks
1. |
Differentiate ` Sin^2 (theta^2 +1)` w.r.t. `theta^2` |
Answer» `y=sin^2(theta^2+1)` `v=theta^2` `dy/dv=((dy)/(d theta))/((dv)/(d theta))` `dy/(dtheta)=sin^2(V+1)=2sin(V+1)*cos(V+1)(dv)/(d theta)` `=2sin(theta^2+1)cos(theta^2+1)` `=sin2(theta^2+1)`. |
|