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Differentiate sin2x w.r.t. x2 |
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Answer» Let u = sin2x, v = x2 Differentiate both w.r.t. x \(\frac{du}{dx}\) = 2 sin x. cos x, \(\frac{dv}{dx}\) = 2x ∴ \(\frac{du}{dv}\) = \(\frac{\frac{du}{dx}}{\frac{dv}{dx}} = \frac{2sinxcosx}{2x}\) = \(\frac{sinxcosx}{x}\) |
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