Solve: y = 4x+y

1.	Solve: y = 4x+y
Answer» Given y = 4^x+y, diff. w r.t. x \(\frac{dy}{dx}\) = 4^{x + y}log4(1 + \(\frac{dy}{dx}\)) = 4^{x + y} \(\frac{dy}{dx}\)(1 - 4^{x + y}log4) = 4^{x + y} log4 ∴ \(\frac{dy}{dx}\) = \(\frac{4^{x + y}.log4}{1 - 4^{x + y}.log4}\)

Answer»

Given y = 4^x+y, diff. w r.t. x

\(\frac{dy}{dx}\) = 4^{x + y}log4(1 + \(\frac{dy}{dx}\)) = 4^{x + y}

\(\frac{dy}{dx}\)(1 - 4^{x + y}log4) = 4^{x + y} log4

∴ \(\frac{dy}{dx}\) = \(\frac{4^{x + y}.log4}{1 - 4^{x + y}.log4}\)

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