InterviewSolution
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InterviewSolution
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displacement at the end of 2 minutes 20 s?We the2. Joseph jogs from one end A to theiogs from one end A to the other end B of a straight200 m road in 2 minutes 30 seconds and then turns aroundand jogs 100 m back to point C in another 1 minute. What areJoseph's average speeds and velocities in jogging (a) from A toB and (b) from A to C? |
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Answer» Velocity = dispacement / timeSpeed = distance / time a) when he jogs from A to B on a straight road,displacement = distance = 300mtime = 2 minutes 30 seconds = 150 s velocity = 300/150 = 2 m/sspeed = 300/150 = 2m/s b)when he jogs from A to B and turns back to C,displacement = 300-100 = 200mdistance = 300+100 = 400mtime = 3 minute 30 second = 210 s velocity = 200/210 = 20/21 m/sspeed = 400/210 = 40/21 m/s Velocity = dispacement / timeSpeed = distance / time a) when he jogs from A to B on a straight road,displacement = distance = 300mtime = 2 minutes 30 seconds = 150 s velocity = 300/150 = 2 m/sspeed = 300/150 = 2m/s b)when he jogs from A to B and turns back to C,displacement = 300-100 = 200mdistance = 300+100 = 400mtime = 3 minute 30 second = 210 s velocity = 200/210 = 20/21 m/sspeed = 400/210 = 40/21 m/s |
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