InterviewSolution
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InterviewSolution
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Divide 124 into four parts in such a way that they are in AP and the product of the first and the 4 th part is 128 less than the product of the 2nd and the 3 rd parts. |
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Answer» Let the four parts be `(a-3d), (a-d) and (a+3d)`. The sum of these four parts is 124, i.e., `4a = 124 rArr a = 31` `(a-3d) (a+ 3d) = (a-d)(a+d)-128` `rArr a^(2) - 9d^(2) = a^(2) - a^(2) - 128` `rArr 8a^(2)= 128 rArr d = pm 4`. As `a = 31`, taking `d=4`, the four parts are 19, 27, 35 and 43. |
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