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Divide a number 1000 in two parts such thatthere product is maximum. |
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Answer» Let the two numbers be x and y so, x+y = 100. => y = 1000-x now for product to be maximum xy should be maximum or x(1000-x) should be maximum so, its differentiation should be 0 => d(x²-1000x)/dx = 0=> 2x -1000 = 0=> x = 1000/2 = 500 so numbers are 500 and 500 |
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