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दो सदिशों ` 2 hati + 3hatj + 4hatk "तथा" 2hati + 4hatj - 4hatk ` के बीच का कोण ज्ञात कीजिए | |
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Answer» माना ` vec a = 2hati + 3hatj + 4hatk ` तथा ` vecb = 2hati + 4hatj - 4hatk ` ` rArr vec a , cecb = 4 + 12 - 16 = 0 ` तथा ` | veca| = sqrt(4 + 9 + 16) = sqrt(29)` तथा `|vecb| = sqrt(4 + 16 +16) = 6` ` therefore cos theta = (veca. vecb)/(|veca|.|vecb|) = (0)/(sqrt(29) xx6) = 0 ` `rArr theta 90^(@)` |
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