InterviewSolution
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InterviewSolution
| 1. |
Draw a comparison between the potential energy and kinetic energy of electrons in the 1^st orbits of hydrogen and He^+ ion. Also comment on the total energy of the electrons in the above cases. |
| Answer» SOLUTION :The electrons revolve round the nucleus with HIGH velocities to counter balance the nuclear force of attraction. As nuclear force of attraction in the `1^(st)` of `He^+` is more than that in H atom. Kinetic energy of electron in `He^(+)` is more (due to greater velocity ) than in H atom. When an electron approaches towards an atom, it LOSES potential works towards the force of attraction. The greater the force of attraction, the more is the loss of potential energy. Hence, the electron in `He^+` has LESSER potential energy than the electron in H atom. But the loss of PE is more SIGNIFICANT than the change in KE. Hence, total energy of helium is less that of hydrogen. | |