Draw v. I graph for an ohmic conductor

1.	Draw v. I graph for an ohmic conductor
Answer» GiveN :- To draw the V - I graph of Ohmic conductor . <P> SolutioN :- We need to draw the V-I graph for an Ohmic conductor . As we know that According to Ohm's Law under same teemerature and other conditions , Potential difference applied across the end of the conductor is directly proportional to the CURRENT flowing through it . That is , $\sf \to \pink{ Voltage \propto Current }$ This implies when we increase the potential difference the current flowing also INCREASES. The constant here is R which is the resistance . That is , $\sf \to \pink{ Voltage = ( Current )(Resistance) }$ This implies that Current is directly proportional to the Voltage . Hence the graph is a straight line passing through the origin O , as the graph SHOWN below or may refer to attachment . G R A P H :- $\boxed{\setlength{\unitlength}{1 cm}\begin{picture}(6,6)\thicklines\put(1,1){\vector(1,0){4}}\put(1,1.001){\vector(0,1){4}}\put(1,0.999){\line(1,1){2.5}} \put(0.3,0.7){$\sf O$ }\put(5.3,1){$\sf I $} \put(1,5.3){$\sf V $} \put(.8,0.2){$\footnotesize{\sf V-I \ graph \ for \ Ohmic \ Conductor}$}\put(3,5){$\boxed{\sf @RishabhRanjan}$} \end{picture} }$ Also note that the ratio of V:I remains constant which is the resistance of the conductor . That is , $\sf\to \pink{ Resistance\gray{(R)} =\dfrac{Voltage\gray{(V)}}{Current\gray{(I)}}= Constant \gray{(C)} }$

Answer»

GiveN :-

To draw the V - I graph of Ohmic conductor .

<P>

SolutioN :-

We need to draw the V-I graph for an Ohmic conductor . As we know that According to Ohm's Law under same teemerature and other conditions , Potential difference applied across the end of the conductor is directly proportional to the CURRENT flowing through it . That is ,

$\sf \to \pink{ Voltage \propto Current }$

This implies when we increase the potential difference the current flowing also INCREASES. The constant here is R which is the resistance . That is ,

$\sf \to \pink{ Voltage = ( Current )(Resistance) }$

This implies that Current is directly proportional to the Voltage . Hence the graph is a straight line passing through the origin O , as the graph SHOWN below or may refer to attachment .

G R A P H :-

$\boxed{\setlength{\unitlength}{1 cm}\begin{picture}(6,6)\thicklines\put(1,1){\vector(1,0){4}}\put(1,1.001){\vector(0,1){4}}\put(1,0.999){\line(1,1){2.5}} \put(0.3,0.7){$\sf O$ }\put(5.3,1){$\sf I $} \put(1,5.3){$\sf V $} \put(.8,0.2){$\footnotesize{\sf V-I \ graph \ for \ Ohmic \ Conductor}$}\put(3,5){$\boxed{\sf @RishabhRanjan}$} \end{picture} }$

Also note that the ratio of V:I remains constant which is the resistance of the conductor . That is ,

$\sf\to \pink{ Resistance\gray{(R)} =\dfrac{Voltage\gray{(V)}}{Current\gray{(I)}}= Constant \gray{(C)} }$