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Dual of the statement (A ∩ B) ∪ (A ∩ \(\bar{B}\)) = A ∩ μ is ……………….A) (A ∪ B) ∪ (A ∪ \(\bar{B}\)) = A ∪ Φ B) (A ∪ B) ∪ (A ∪ \(\bar{B}\)) = A ∪ Φ C) (A ∪ B) ∪ (A ∪ \(\bar{B}\)) = A ∪ μ D) (A ∩ B) ∩ (A ∩ \(\bar{B}\)) = A ∪ Φ |
Answer» Correct option is A) (A ∪ B) ∪ (A ∪ \(\bar{B}\)) = A ∪ Φ |
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