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Dues 4- Calculate the voltage require to balance a oildrop carrying loe when located b/w plates of acapacitor which are 5 mm apart. Given mass ofdrop is 3x10^16 kg(9.2 volts) |
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Answer» The gravitational force on the oil drop = mg = 3 x 10^-16x 10 = 3 x 10^-15N. Magnitude of the electrostatic force needed balance this force is given by E = mg/10e = (3 x 10^-15) / (10 x 1.6 x 10^-19) = 0.1875 x 10^4V/m. Voltage across the places of the capacitor is then given by V = Ed = 0.1875 x 10^4x 5 x 10^-3= 9.375 Volts. |
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