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During electrolysis of aqueous `CuBr_(2)` using `Pt` electrode,A. `Br_(2)` gas is evolved at the anodeB. `Cu(s)` is deposited at the cathodeC. `Br_(2)` gas is evolved at anode and `H_(2)` gas at cathodeD. `H_(2)` gas is evolved at anode. |
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Answer» Correct Answer - A::B (A,B) at cathode: `Cu^(2+)+2e^(-)toCu(s)` `underline(2Br^(-)+toBr_(2)2e^(-))` `Cu^(2+)+2Br^(-)toBr_(2)+Cu(s)`. |
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