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`(dy)/(dx)=cos^(-1)x` |
Answer» `(dy)/(dx)=sin^(-1)x` `implies dy=sin^(-1)x.dx` `implies int dy=int1. sin^(-1)x dx+c` `implies y=sin^(-1)x.int1 dx-int((d)/(dx)sin^(-1)x)(int1.dx)dx+c` `implies y=x sin^(-1)x` `-int(x)/(sqrt(1-x^(2)))dx+c` `impliesy=xsin^(-1)x-int(-dt)/(2sqrt(t))+c` `implies y=x sin^(-1)x+(1)/(2)t^(-1//2)dt+c` `implies y=x sin^(-1)x+sqrt(t)+c` `implies y=xsin^(-1)x+sqrt(1-x^(2))+c` |
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