1.

`(dy)/(dx)=y tan x , y = 2` यदि x = 0

Answer» दिया है, `(dy)/(dx)=y tan x`
`implies (1)/(y)dy=tan xdx`
`implies int (1)/(y) dy = int tan x dx`
`implies log|y|==log|(secx)|+log|C|`
`implies logy=log|(C sec x)|`
`impliesy=Csecx`
अब, y = 1 तथा x = 0 रखने पर,
1 = C sec 0 implies `1 = C xx 1 implies C = 1`
C = 1 रखने पर, y = sec x
जोकि अभीष्ट विशिष्ट हल है।


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