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DYNAMICS-IIA body of mass 3 kg is under the action of a force which causes a displacement in it given byS- (in m) tind the work done by the force in first 2 seconds(1) 2J(2) 3.8J(3) 5.2J(4) 2.6Jofluence of a force given by

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We are given displacement-time relation : s = (1/3) × t² Differentiating it wrt time t ; we get velocity - time relation :-v = (2/3)×t again differentiating above wrt time t ; we get acceleration of body :-a = 2/3 m/s² Now ;Force = mass × acceleration = 3× (2/3) = 2 Nusing displacement-time relation and putting the t = 2 ; we get the displacement the body covers in 2 seconds .s = (1/3) (2)²s = 4/3 m______________________Now work done = 2 × 4/3= 8/3 J



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