1.

e o o bedy collides with a bu{t, ;J'. Appon Coliion ey Fove]cbhen with o velodly of One thad bheity of kg T Thenmy WÂŤ -

Answer»

This is a question on momentum.

By law of conservation of linear momentum:

Initial momentum = Final momentum

Momentum = mass × velocity

Initial momentum:For the person = 0 × 6 = 0

Let v be the velocity of the particle and m the mass of the particle.

Its momentum = mv

Final momentum The final speed = 1/3 × 6 = 2

Final momentum = (m + 6)2

= 2m + 12

Equating the two2m + 12 = vm

Vm - 2m = 12

M (v - 2) = 12

m = 12/(v - 2) kg



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