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e o o bedy collides with a bu{t, ;J'. Appon Coliion ey Fove]cbhen with o velodly of One thad bheity of kg T Thenmy WÂŤ - |
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Answer» This is a question on momentum. By law of conservation of linear momentum: Initial momentum = Final momentum Momentum = mass × velocity Initial momentum:For the person = 0 × 6 = 0 Let v be the velocity of the particle and m the mass of the particle. Its momentum = mv Final momentum The final speed = 1/3 × 6 = 2 Final momentum = (m + 6)2 = 2m + 12 Equating the two2m + 12 = vm Vm - 2m = 12 M (v - 2) = 12 m = 12/(v - 2) kg |
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