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Efficiency of carnot engine working between ice point and steam point isA. 0.249B. 0.257C. 0.268D. 0.288

Answer» Correct Answer - C
Here ice point ,`T_(2)=0^(@)C = 0 +273 =273 K` and steam point, `T_(1)=100^(@)C=100+273=373 K` Efficiency of the cannote engine
`eta=1-(T_(2))/(t_(1))=1-(273)/(373)=(100)/(373)=(100)/(373)xx100%=26.8%`


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