Eight Mercury drops of equal radius and equal charge combine to form a – InterviewSolution

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1.	Eight Mercury drops of equal radius and equal charge combine to form a big drop. The capacitance of big drop in comparison the each small drop will be:(a) 2 times(b) 8 times(c) 4 times(d) 16 times
Answer» (a) 2 times Volume of big drop = 8 × Volume of small drop \(\frac{4}{3}\)πR³ = 8 × \(\frac{4}{3}\)πr³ R = 2r Capacitance of small drop C₁ = 4πε₀r Capacitance of bigger drop C₂ = 4πε₀R \(\frac{C_{1}}{C_{2}}=\frac{r}{R}=\frac{r}{2 r}\) C₂ = 2C₂

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Eight Mercury drops of equal radius and equal charge combine to form a big drop. The capacitance of big drop in comparison the each small drop will be:(a) 2 times(b) 8 times(c) 4 times(d) 16 times