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The potential energy between plates of a charged parallel plate capacitor is UQ. If a dielectric plate of dielectric constant er is placed between The gap of plates, then the new potential energy will be :(a) \(\frac{U_{0}}{\varepsilon_{r}}\)(b) U0εr2(c) \(\frac{U_{0}}{\varepsilon_{r}^{2}}\)(d) U0 |
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Answer» (a) \(\frac{U_{0}}{\varepsilon_{r}}\) |
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