electric heater of resistance 8 ohm draws 15 on from the service mains

1.	electric heater of resistance 8 ohm draws 15 on from the service mains in 2 hours calculate the rate at which heat is developed in the heater
Answer» <P>R= 8ohm , I= 15A , T= 2hr V= IR. (Ohm's law) V= 15×8 V= 120volts Now, P= VI P= 120×15 P= 1800 WATT (W) Used for 2 hour for 30 days = 1800×2/1000 = 3.6 × 30 = 108 kWh To find COST for RUPEES 5 per unit = 108×5 = ₹540

electric heater of resistance 8 ohm draws 15 on from the service mains in 2 hours calculate the rate at which heat is developed in the heater

Answer»

<P>R= 8ohm , I= 15A , T= 2hr

V= IR. (Ohm's law)

V= 15×8

V= 120volts

Now,

P= VI

P= 120×15

P= 1800 WATT (W)

Used for 2 hour for 30 days

= 1800×2/1000

= 3.6 × 30

= 108 kWh

To find COST for RUPEES 5 per unit

= 108×5

= ₹540

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electric heater of resistance 8 ohm draws 15 on from the service mains in 2 hours calculate the rate at which heat is developed in the heater​

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electric heater of resistance 8 ohm draws 15 on from the service mains in 2 hours calculate the rate at which heat is developed in the heater