. electric iron of 50 ohm and a toaster of 100 ohm are connected in parallel the power source 10 V. current across each appliances.

. electric iron of 50 ohm and a toaster of 100 ohm are connected in

1.	. electric iron of 50 ohm and a toaster of 100 ohm are connected in parallel the power source 10 V. current across each appliances.
Answer» n(1) Total RESISTANCE (R) can be calculated as shown below.1/R = 1/R₁ + 1/R₂ + 1/R₃1/R = 1/100 + 1/50 + 1/5001/R = ( 5 + 10 + 1 )/5001/R = 16/500500/16 = RTotal Resistance (R) = 500/16 ΩR = 31.25 Ω(2) According to ohm’s law the current through a conductor between two points is directly proportional to the voltage across the two points.V ∝ I or V = IRR is constant called resistance.R = V/I500/16 = 220/II = 220 × (16/500)I = 7.04 ATherefore, the resistance of the electric IRON is 31.25 Ω and the current flowing through it is 7.04 A.

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. electric iron of 50 ohm and a toaster of 100 ohm are connected in parallel the power source 10 V. current across each appliances. ​

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. electric iron of 50 ohm and a toaster of 100 ohm are connected in parallel the power source 10 V. current across each appliances.