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Electric potential at any point is `V = - 5 x + 3y + sqrt(15) z`, then the magnitude of the electric field isA. `3 sqrt(2)`B. `4 sqrt(2)`C. `5sqrt(2)`D. `7` |
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Answer» Correct Answer - D `E_(x) = - (dV)/(dx) = - (-5) = 5, E_(y) = - (dV)/(dy) = - 3` and `E_(z) = - (dV)/(dz) = - sqrt(15)` `E_("net") = sqrt(E_(x)^(2) + E_(y)^(2) + E_(z)^(2)) =sqrt((5)^(2) + (-3)^(2) + (-sqrt(15)^(2))) =7` |
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