Saved Bookmarks
| 1. |
Electron accelerate by potential difference of 250 V enter the electric field at angle of incidence of 50 degree and get refracted through an angle of 30 degree . Find the potential of second region. *585.2 V600 V700 V500 V |
|
Answer» angle of INCIDENCE of 50 degree and get refracted through an angle of 30 degree . Find the POTENTIAL of second REGION
the answer is = 700v |
|