1.

Eliminate 0 from the following: x = 5 + 6 cosec θ,y = 3 + 8 cot θ

Answer»

x = 5 + 6cosec θ and y = 3 + 8cot θ 

∴ x – 5 = 6cosec θ and y – 3 = 8cot θ

∴ cosec θ = \(\frac{x-5}{6}\) and cot θ \(\frac{y-3}{8}\)

We know that,

cosec2 θ – cot2 θ = 1

 ∴ \((\frac{x-5}{6})^2 - (\frac{y-3}{8})^2=1\)



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