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Eliminate 0 from the following: x = 5 + 6 cosec θ,y = 3 + 8 cot θ |
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Answer» x = 5 + 6cosec θ and y = 3 + 8cot θ ∴ x – 5 = 6cosec θ and y – 3 = 8cot θ ∴ cosec θ = \(\frac{x-5}{6}\) and cot θ \(\frac{y-3}{8}\) We know that, cosec2 θ – cot2 θ = 1 ∴ \((\frac{x-5}{6})^2 - (\frac{y-3}{8})^2=1\) |
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