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Eliminate `theta` from the equation `P=a "cosec" theta nd Q=a cot theta`. |
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Answer» Given , `P= a " cosec" theta and Q=a cot theta ` `(P)/(a)="cosec" theta and (Q)/(a)= cot theta `. We know that , `"cosec"^(2)theta- cot^(2)theta=1` `((P)/(a))^(2)-((Q)/(a))^(2)=1` Hene, the required relation is `P^(2)-Q^(2)=a^(2)`. |
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