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1. |
Enthalpy change for the process, `H_(2)O"(ice")hArr H_(2)O"(water)"` is `"6.01 kJ mol"^(-1)`. The entropy change of 1 mole of ice at its melting point will beA. `"12 J K"^(-1)"mol"^(-1)`B. `"22 J K"^(-1)"mol"^(-1)`C. `"100 J K"^(-1)"mol"^(-1)`D. `"30 J K"^(-1)"mol"^(-1)` |
Answer» Correct Answer - B `DeltaS_("fusion")=(DeltaH_("fusion"))/(T_("fusion"))=(6.01xx1000)/(273)` `="22 J K"^(-1)"mol"^(-1)` |
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