Enthalpy of combustion of carbon to `CO_(2)` is `-393.5 kJ mol^(-1)`. Calculate the heat released upon formation of `35.2 g` of `CO_(2)` from carbon and dioxygen gas.A. `-315 KJ`B. `+315KJ`C. `-630 KJ`D. `-3.15 KJ`

Enthalpy of combustion of carbon to `CO_(2)` is `-393.5 kJ mol^(-1)`.

1.	Enthalpy of combustion of carbon to `CO_(2)` is `-393.5 kJ mol^(-1)`. Calculate the heat released upon formation of `35.2 g` of `CO_(2)` from carbon and dioxygen gas.A. `-315 KJ`B. `+315KJ`C. `-630 KJ`D. `-3.15 KJ`
Answer» Correct Answer - A Given, `C(s) + O_(2)(g) to CO_(2)(g)` , `Delta_(f)H=-393.5 KJ "mol"^(-1)` Heat released on formation of 44 g or 1 mole `CO_(2) =- 395.5 KJ "mol"^(-1)` `because ` Heat released on formation of 35.2 g of `CO_(2)` `=(-393.5 KJ "mol"^(-1))/(44 g) xx35.2 g =- 315 KJ "mol"^(-1)`

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Enthalpy of combustion of carbon to `CO_(2)` is `-393.5 kJ mol^(-1)`. Calculate the heat released upon formation of `35.2 g` of `CO_(2)` from carbon and dioxygen gas.A. `-315 KJ`B. `+315KJ`C. `-630 KJ`D. `-3.15 KJ`

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