Entropy change for reversible phase transition at constant pressure P and temperature T is calculated by the formula `DeltaS=(DeltaH)/(T),` where `DeltaH` is the enthalpy change for phase transition. For irreversible phase transition `DeltaSgt(DeltaH)/(T).` Consider a phase transition. `Sn("white",s)iffSn("grey,s")` `DeltaH^(@) `at 1 atm and` 300K=-2 kJmol^(-1)` The equilibrium temperature at 1 atm is 400 K. Assume `C_(p,m)` of Sn (white,s) and Sn(grey,s) are equal. `DeltaS^(@)` for above phase transition at 1 atm and 300K is :A. `-5JK^(-1)mol^(-1)`B. `-(20)/(3)JK^(-1)mol^(-1)`C. `-0.0055JK^(-1)mol^(-1)`D. `-(2000)/(3)JK^(-1)mol^(-1)`

Entropy change for reversible phase transition at constant pressure P

1.	Entropy change for reversible phase transition at constant pressure P and temperature T is calculated by the formula `DeltaS=(DeltaH)/(T),` where `DeltaH` is the enthalpy change for phase transition. For irreversible phase transition `DeltaSgt(DeltaH)/(T).` Consider a phase transition. `Sn("white",s)iffSn("grey,s")` `DeltaH^(@) `at 1 atm and` 300K=-2 kJmol^(-1)` The equilibrium temperature at 1 atm is 400 K. Assume `C_(p,m)` of Sn (white,s) and Sn(grey,s) are equal. `DeltaS^(@)` for above phase transition at 1 atm and 300K is :A. `-5JK^(-1)mol^(-1)`B. `-(20)/(3)JK^(-1)mol^(-1)`C. `-0.0055JK^(-1)mol^(-1)`D. `-(2000)/(3)JK^(-1)mol^(-1)`
Answer» Correct Answer - a

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