Equal heat is given to two objects A and B of mass 1g. Temperature of A increases by 3^@C and B by 5^@C. Which object has more specific heat? And by what factor?

Equal heat is given to two objects A and B of mass 1g. Temperature of

1.	Equal heat is given to two objects A and B of mass 1g. Temperature of A increases by 3^@C and B by 5^@C. Which object has more specific heat? And by what factor?
Answer» Solution :Given : Heat given to A = Heat given to B Change in Temperature of A =`DeltaT_A=3^@C` Change in Temperature of B =`DeltaT_B=5^@C` To Find: (i)Object with more specific heat (ii)Change in the FACTOR FORMULA : Heat = mass of water X specific heat x change in temperature = m x c x `Delta`T Solution: Heat given to A =Heat given to B `m_Axxc_AxxDeltaT_A = m_Bxxc_BxxDeltaT_B` `1 xx c_A xx 3 = 1 xx c_B xx 5` `3c_A=5c_B` `c_A/c_B=5/3` Hence , specific heat of A is greater than specific heat of B. Also , specific heat of A is greater than specific heat of B by a factor of `5/3`