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Equal masses of oxygen and helium gases are supplied equal amount of heat. Which gas will undergo a greater temperature rise and why? |
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Answer» Solution :Heat SUPPLIED to oxygen `=` Heat supplied to Helium `mc_(1)DeltaT_(1)=mc_(2)DeltaT_(2)` `(DeltaT_(1))/(DeltaT_(2))=(c_(2))/(c_(1))`, As `CXX(1)/(m)`, `m=` molecular mass `(DeltaT_(1))/(DeltaT_(2))=(c_(2))/(c_(1))=(m_(1))/(m_(2))`, As `m_(1) gt m_(2)` `DeltaT_(1) gt DeltaT_(2)` |
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