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Equal moles of H2O and NaCl are present in a solution hence molality of NaCl is |
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Answer» a/c to question, equal MOLES of H2O and NaCl are present in a solution. Let N moles of NaCl are present in n moles of H2O solution. so, number of moles of NaCl(SOLUTE) = n mass of water (SOLVENT ) =number of moles of H2O × molar mass of H2O = n × 18 = 18n grams [ as you know, molar mass of H2O = 18g/mol] use formula, molality = number of mole of solute/mass of solvent in Kg = n × 1000/(18n ) = 1000/18 = 55.55 molal hence, molality of NaCl is 55.55m. |
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