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Equal moles of H2O and NaCl are present in a solution hence molality of NaCl is ​

Answer»

a/c to question, equal MOLES of H2O and NaCl are present in a solution.

Let N moles of NaCl are present in n moles of H2O solution.

so, number of moles of NaCl(SOLUTE) = n

mass of water (SOLVENT ) =number of moles of H2O × molar mass of H2O

= n × 18 = 18n grams [ as you know, molar mass of H2O = 18g/mol]

use formula, molality = number of mole of solute/mass of solvent in Kg

= n × 1000/(18n )

= 1000/18

= 55.55 molal

hence, molality of NaCl is 55.55m.



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